6/4/2023 0 Comments Popkey ordereddict![]() ![]() # from dummy_thread import get_ident as _get_identįrom _thread import get_ident as _get_ident # Changed - martineauįrom _abcoll import KeysView, ValuesView, ItemsView # Passes Python2.7's test suite and incorporates all the latest updates.įrom thread import get_ident as _get_ident # Backport of OrderedDict() class that runs on Python 2.4, 2.5, 2.6, 2.7 and pypy. Prepend() can also be implemented directly, almost exactly as shown at the beginning of Chaudhary's answer-and doing so would likely result in it being slightly faster, but that's been left as an exercise for the motivated reader. As a bonus, I also made a few additional minor changes to get to work in both Python 2.7.15 and 3.7.1.Ī prepend() method has been added to the class in the recipe and has been implemented in terms of another method that's been added named move_to_end(), which was added to OrderedDict in Python 3.2. To prove this approach is feasible, below is code that does what's suggested. The code to do so could be a fairly efficient given that the underlying data structure for ordering is a linked-list. I would suggest adding a prepend() method to this pure Python ActiveState recipe or deriving a subclass from it. New_dic = OrderedDict((k, d2.get(k, d1.get(k))) for k in \ # unique_everseen('ABBCcAD', str.lower) -> A B C Dįor element in ifilterfalse(seen._contains_, iterable):ĭ1 = OrderedDict()ĭ2 = OrderedDict() #dict containing items to be added at the front # unique_everseen('AAAABBBCCDAABBB') -> A B C D If you don't want to do that and performance is not an issue then easiest way is to create a new dict: from itertools import chain, ifilterfalse
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